Home/Study Plan/Clock, Angle & Number Puzzles
🧠

Brainteasers & Logic

Clock, Angle & Number Puzzles

Easy2–3 hrsClockAnglesNumber TheoryDivisibility

Overview

Clock puzzles are geometry problems in disguise — translate to angles with a simple formula and the hard part vanishes. Number puzzles about last digits or remainders are modular arithmetic: find the repeating cycle and reduce. Both reward writing a clean equation rather than staring at the problem.

How to Recognize

  • Clock hand angles at a specific time
  • 'How many times do clock hands overlap in 12 hours?'
  • Last-digit and remainder puzzles
  • Self-referential number properties

Step-by-Step Approach

  1. 1.Clock: minute hand moves 6°/min; hour hand moves 0.5°/min
  2. 2.Angle between hands: |30H − 5.5M| degrees (take min with 360 minus this)
  3. 3.Hands overlap: every 720/11 minutes → exactly 11 times per 12-hour period
  4. 4.For last-digit/remainder: find the cycle length and use modular arithmetic

Key Formulas

01Hour hand: 30H+0.5M30H + 0.5M degrees from 12
02Angle between hands: 30H5.5M|30H - 5.5M| (degrees)
03Overlaps in 12 hrs: 1111 (every 720/1165.45720/11 \approx 65.45 min)
04Last digit of ana^n: find cycle mod 10, compute nmodcycle lengthn \bmod \text{cycle length}

Worked Examples

0Quick Example
Angle at 3:15 = |30×3 − 5.5×15| = |90 − 82.5| = 7.5°. Hands are nearly overlapping.

Problem

What is the angle between the clock hands at 2:20?

Solution

1

Hour hand at 2:20: 30×2 + 0.5×20 = 60 + 10 = 70° from 12.

2

Minute hand at 2:20: 6×20 = 120° from 12.

3

Angle = |120 − 70| = 50°. Less than 180°, so 50° is the answer.

4

Formula shortcut: |30H − 5.5M| = |30×2 − 5.5×20| = |60 − 110| = 50°. ✓

Answer

50 degrees. Shortcut: 30H5.5M=60110=50°|30H - 5.5M| = |60-110| = 50°.

Common Mistakes

  • !

    Saying clock hands overlap 12 times in 12 hours — it's 11. They don't overlap every 60 minutes.

  • !

    Forgetting to take the smaller angle: always report min(angle, 360°−angle).

  • !

    Off-by-one in cycle position: if n mod cycleLength = 0, use the LAST element of the cycle, not the first.

Practice Problems

Click "Show Answer" to reveal
1

What is the angle between clock hands at 6:30?

Hint: |30H − 5.5M| with H=6, M=30.
2

What is the last digit of 9^{999}?

Hint: Cycle for 9 mod 10: 9,1,9,1,... (length 2).
3

At what time between 3 and 4 o'clock are the hands exactly perpendicular (90°)?

Hint: |30×3 − 5.5M| = 90 or 270. Solve for M.

Only works in the Electron app

<webview> is an Electron-only tag. Run npm run electron:dev to use this.

25:00Focus
0

25 min focus · 5 min break · long break every 4 sessions

The Ultimate Grind